Erdős Problem a Daythe open tracker

Erdős Problem #980

PROVEDdatabase updated 2025-09-03

The statement as posed is true, and a proof exists.

What the community database records, not our verdict. erdosproblems.com no longer shows statuses (why).

\(n_k(p)\): the least positive integer which is not a \(k\)-th power residue modulo \(p\). If every integer is a \(k\)-th power residue (for example if \(\gcd(k, p - 1) = 1\)) the value is \(0\); this does not happen for the primes \(p \equiv 1 \pmod k\) with \(k \geq 2\) used below.

\(\sum n_k(p)\) over the primes \(p < x\) with \(p \equiv 1 \pmod k\).

Let \(k\geq 2\) and \(n_k(p)\) denote the least \(k\)th power nonresidue of \(p\). Is it true that \[\sum_{p<x} n_k(p)\sim c_k \frac{x}{\log x}\] for some constant \(c_k>0\)? Erdős [Er65b] asked this; it is true, and was proved by Elliott [El67b]. As in [El67b], the sum is over the primes \(p \equiv 1 \pmod k\) (for each of which a \(k\)th power nonresidue exists).
Statement as formalized in Formal Conjectures (Google DeepMind, Apache-2.0) · their label: research solved · 1 further variant / known partial result in the Lean file. The authoritative wording is on erdosproblems.com/980.
Prizenone
Topicsnumber theory
Statement in LeanFormal Conjectures
Solution in Leanno
OEISA053760, A098990
Original pageerdosproblems.com/980
NOBODY HAS SENT US AN ATTEMPT YET

If you take a run at this one — with your own AI subscription or without — the guide says how, and the submission form gets you an honest read of what you found.